Solutions to exercises for the Part II course Temporal Logic and Model Checking
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چکیده
SDIV = [0..5] × Z× Z× Z× Z (where [m..n] = {m,m+1, . . . , n}) R̂DIV (pc, x, y, r, q) (pc ′, x′, y′, r′, q′) = (pc = 0) ⇒ ((pc′, x′, y′, r′, q′) = (1, x, y, x, q)) ∧ (pc = 1) ⇒ ((pc′, x′, y′, r′, q′) = (2, x, y, r, 0)) ∧ (pc = 2) ⇒ ((pc′, x′, y′, r′, q′) = if y≤r then (3, x, y, r, q) else (5, x, y, r, q)) ∧ (pc = 3) ⇒ ((pc′, x′, y′, r′, q′) = (4, x, y, (r−y), q)) ∧ (pc = 4) ⇒ ((pc′, x′, y′, r′, q′) = (2, x, y, r, (q+1)) ∧ (pc / ∈ [0..4]) ⇒ ((pc′, x′, y′, r′, q′) = (pc, x, y, r, q)
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Solutions to exercises for the Part II course Temporal Logic and Model Checking
SDIV = [0..5] × Z× Z× Z× Z (where [m..n] = {m,m+1, . . . , n}) R̂DIV (pc, x, y, r, q) (pc ′, x′, y′, r′, q′) = (pc = 0) ⇒ ((pc′, x′, y′, r′, q′) = (1, x, y, x, q)) ∧ (pc = 1) ⇒ ((pc′, x′, y′, r′, q′) = (2, x, y, r, 0)) ∧ (pc = 2) ⇒ ((pc′, x′, y′, r′, q′) = if y≤r then (3, x, y, r, q) else (5, x, y, r, q)) ∧ (pc = 3) ⇒ ((pc′, x′, y′, r′, q′) = (4, x, y, (r−y), q)) ∧ (pc = 4) ⇒ ((pc′, x′, y′, r′, ...
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